A Simple Model of the Odds of Passing an Evaluation
Posted: Sun Oct 25, 2026 8:21 am
A Simple Model of the Odds of Passing an Evaluation
Model an evaluation as a walk where each trade wins or loses 1R, with a target of plus 8R and a failure at minus 10R. If the win probability is p, the chance of hitting the target first is given by a standard result. Let the ratio of loss to win probability be r equals q divided by p. The probability is (1 minus r to the power of 10) divided by (1 minus r to the power of 18).
At p equals 0.50, r is 1, and the formula reduces to 10 divided by 18, which is 55.6 percent.
At p equals 0.52, r is 0.923. Then r to the 10th is about 0.449, and r to the 18th is about 0.237. The probability is (1 minus 0.449) divided by (1 minus 0.237), which is 0.551 divided by 0.763, about 72 percent.
At p equals 0.55, r is 0.818. r to the 10th is about 0.134, and r to the 18th is about 0.027. The probability is 0.866 divided by 0.973, about 89 percent.
Notice how steeply the odds depend on a small edge. A coin-flip strategy passes just over half the time in this simplified model. A strategy winning 55 percent of 1R trades is far better.
What the model leaves out: time limits, daily loss rules, payoffs that are not symmetric, streak dependence, and costs. Each lowers the real pass rate.
Costs matter especially. If each trade costs 0.1R, a 55 percent win rate effectively becomes 50 percent.
Exercise: modify the target and the floor, and see how the pass rate changes at a fixed win probability.
Model an evaluation as a walk where each trade wins or loses 1R, with a target of plus 8R and a failure at minus 10R. If the win probability is p, the chance of hitting the target first is given by a standard result. Let the ratio of loss to win probability be r equals q divided by p. The probability is (1 minus r to the power of 10) divided by (1 minus r to the power of 18).
At p equals 0.50, r is 1, and the formula reduces to 10 divided by 18, which is 55.6 percent.
At p equals 0.52, r is 0.923. Then r to the 10th is about 0.449, and r to the 18th is about 0.237. The probability is (1 minus 0.449) divided by (1 minus 0.237), which is 0.551 divided by 0.763, about 72 percent.
At p equals 0.55, r is 0.818. r to the 10th is about 0.134, and r to the 18th is about 0.027. The probability is 0.866 divided by 0.973, about 89 percent.
Notice how steeply the odds depend on a small edge. A coin-flip strategy passes just over half the time in this simplified model. A strategy winning 55 percent of 1R trades is far better.
What the model leaves out: time limits, daily loss rules, payoffs that are not symmetric, streak dependence, and costs. Each lowers the real pass rate.
Costs matter especially. If each trade costs 0.1R, a 55 percent win rate effectively becomes 50 percent.
Exercise: modify the target and the floor, and see how the pass rate changes at a fixed win probability.